Question

Solve on the interval (0,2pi): sinx-2=cosx-2
When I did this I got tan(x)=0 with solutions o, pi, 2pi

Answer 1

u r going to get tanx =1

Answer 2

Doesn't -2 cancel and become 0 when I add 2 to one side?

Answer 3

sinx = cosx-2+2
sinx = cosx
now divide both sides by cosx

Answer 4

now u will get tanx = 1

Answer 5

as tanx is positive ,therefore, x will lie in first and third quadrant

Answer 6

Okay so I came up with the solutions pi/4+pi n, 5pi/4 + pi n. Is that correct?

Answer 7

u r going to get pi/4 and 5pi/4