Ask your own question, for FREE!
Mathematics 10 Online
OpenStudy (anonymous):

Can someone PLEASE help me out?! medal AND fan!!

OpenStudy (anonymous):

OpenStudy (muhammad_nauman_umair):

so [-30 -5 ] [-20 - 4 ] [+20 +30] + [-12 -32 ] [-35 +35] [ 24 +32 ]

OpenStudy (anonymous):

woah wait.. how in the world did you get that?

OpenStudy (muhammad_nauman_umair):

now we have to add these two matrices to get the answer

OpenStudy (anonymous):

oook.. i think i see how you got that now.. you multiplied everything in the first matrix by - 5 right?

OpenStudy (muhammad_nauman_umair):

ok simply multiply the elements of matrix A with -5 and B with +4 we get the above rresult

OpenStudy (anonymous):

ooh ook.. and now just add them to get the answer?:)

OpenStudy (muhammad_nauman_umair):

yes

OpenStudy (anonymous):

ok hold on...

OpenStudy (muhammad_nauman_umair):

ok

OpenStudy (anonymous):

-50 -9 8 -2 59 67

OpenStudy (anonymous):

right?

OpenStudy (anonymous):

but thats not an option.. these r the options i have:

OpenStudy (muhammad_nauman_umair):

[-50 -9] [8 - 2 ] [-11 +67]

OpenStudy (muhammad_nauman_umair):

simply your addition was wrong

OpenStudy (anonymous):

ooooh i forgot the negative sign on the last one.. ok.. Thanks so much!!:) can you help me with more please?:)

OpenStudy (anonymous):

OpenStudy (muhammad_nauman_umair):

ok i m waiting for the next one

OpenStudy (anonymous):

i posted it :)

OpenStudy (muhammad_nauman_umair):

now multiply 2 with the matrix

OpenStudy (muhammad_nauman_umair):

take the result on the other side

OpenStudy (muhammad_nauman_umair):

after solving the subtraction of two matrices we get a matrix which will be divided by 2 and hence X will b found

OpenStudy (anonymous):

ok.. i got 4 -16 -8 4 for the first part..

OpenStudy (muhammad_nauman_umair):

yes

OpenStudy (anonymous):

now what?

OpenStudy (muhammad_nauman_umair):

take this matrix on the other side

OpenStudy (anonymous):

what does that mean? like i add it with the other one?

OpenStudy (muhammad_nauman_umair):

if u have the case like X +Y =Z what u do is to find X X= Z-Y

OpenStudy (anonymous):

oh so subtract the 1st one with the 2nd one?

OpenStudy (muhammad_nauman_umair):

yes

OpenStudy (anonymous):

ok i got 0 -22 -10 12 is that right?

OpenStudy (anonymous):

no.. its not an option..:/

OpenStudy (muhammad_nauman_umair):

no

OpenStudy (anonymous):

what did i do wrong?

OpenStudy (muhammad_nauman_umair):

here y is the matrix u got by multiplying by 2 and the matrix on the right side is Z so u have to do Z-Y

OpenStudy (anonymous):

could you please show me how?

OpenStudy (muhammad_nauman_umair):

[4 -6] - [4 -16] [2 -8] [-8 4]

OpenStudy (anonymous):

i got 0 -22 10 -12 but thats not an option either.

OpenStudy (muhammad_nauman_umair):

0 10 10 -12

OpenStudy (anonymous):

thats still not an option?

OpenStudy (muhammad_nauman_umair):

u again made mistake in addition and subtraction

OpenStudy (anonymous):

the one you posted wasnt an option either..

OpenStudy (muhammad_nauman_umair):

this wholle thing is 2X now u have to divide it by two to get the answer

OpenStudy (muhammad_nauman_umair):

got it or not?

OpenStudy (anonymous):

i guess so.. heres another one

OpenStudy (muhammad_nauman_umair):

the third one was the answer

OpenStudy (anonymous):

r u sure? can you tell me how you figured it out?

OpenStudy (muhammad_nauman_umair):

answer for the last question was the third option do u still have problem in the last question ? problem 2

OpenStudy (anonymous):

yea i got that, thanks:) i need help on the next question that i posted:)

OpenStudy (muhammad_nauman_umair):

ok

OpenStudy (muhammad_nauman_umair):

do u know how to multiply a matrices

OpenStudy (anonymous):

yep

OpenStudy (muhammad_nauman_umair):

then here we go

OpenStudy (muhammad_nauman_umair):

In question matrix is given [TD=6 FG=3 S=2 PAT=1] this is of order 1*4

OpenStudy (muhammad_nauman_umair):

for team A [TD=3 FG=2 S=1 PAT=0] when we write it in horizontal way like the above one we don't fulfill the condition of multiplication i.e no. of colums of 1st matrix = no. of rows of 2nd matrix so we have to write in this way [ TD=3 ] [ FG=2 ] [ S=1 ] [ PAT=0 ] of order 4*1 by multiplying this vector with the above one we will get what is required

OpenStudy (muhammad_nauman_umair):

[6 3 2 1] * [ 3 ] [ 2 ] [ 1 ] [ 0 ]

OpenStudy (muhammad_nauman_umair):

now multiply them and get the answer for team A

OpenStudy (anonymous):

i got 36..

OpenStudy (anonymous):

and thats an option!! thanks so much!!:)

OpenStudy (muhammad_nauman_umair):

no no no its 26

OpenStudy (muhammad_nauman_umair):

[18+ 6+2 +0] = 26

OpenStudy (anonymous):

ooh.. well that's still an option.. thanks!!:)

OpenStudy (muhammad_nauman_umair):

now did u get the method to solve it ?

OpenStudy (muhammad_nauman_umair):

i never tried so hard to make someone learn something . Now i can go sleep with ease..

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!