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i have a question, please hep. question in comment.(medal and fans)
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whats is the area of the figure?
A.520 in2 B.280 in2 C.501 in2 D.436 in2
lets break up the picture
so first lets do 14 * 20
for the big rectangle on the bottom
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280
OK now the squarish thing on the top
what is 26-14
12?
ok so the missing length of the squarish thing is 12
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what is 12 * 13
156?
add 280 (rectangle) + 156 (squarish) = 436 in 2 (answer D)
ooohhhh. ok i get it now thank you so very much
welcome milady
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lol.
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