Please Help! (3w+5)^2
(x+y)^2 = x^2 + 2xy + y^2
so would that be the FOIL method?
The formula in my first reply is an algebraic identity. You need the foil method only when you want to multiply out (3w+5)(3w+5). Either way you will get the same answer after simplification. But the identity method will be faster.
if it wont take too much time, can you tell me what the identity method is?
(x+y)^2 = x^2 + 2xy + y^2 The identity says: square the first term + 2 * (first term) * (second term) + square the second term. (3w + 5)^2 = (3w)^2 + 2 * 3w * 5 + (5)^2 = ?
ok thanks
so i got 9w+30w+25
(3w + 5)^2 = (3w)^2 + 2 * 3w * 5 + (5)^2 = 9w^2 + 30w + 25
ok thanks so much :D
You are welcome. If you FOIL it and simplify you will get the same answer: (3w+5)^2 = (3w+5) * (3w+5) = (3w)(3w) + (3w)(5) + (5)(3w) + (5)(5) = 9w^2 + 15w + 15w + 25 = 9w^2 + 30w + 25.
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