Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x^2/3 + y^2/3 = 4, (-3√3, 1)

Question

Use implicit differentiation to find an equation of the tangent line to the curve at the given point.  x^2/3 + y^2/3 = 4,  (-3√3, 1)

anonymous · Answer

$$
\frac{2
   x}{3}+\frac{2}{3} y y'=0
$$

anonymous · Answer

$$
y'=-\frac x y=-\frac{ -3\sqrt3}1= 3 \sqrt3
$$

anonymous · Answer

$$
y-1 = 3 \sqrt 3 (x + 3\sqrt 3)\
y=3 \sqrt 3  x+ 28
$$