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Mathematics 28 Online
OpenStudy (anonymous):

determine convergence of series= sin^n(1/n) n=1

OpenStudy (anonymous):

converges for sure you do mean the sum right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

then since \(\sin(x)<1\) you can compare it to any geometric series

OpenStudy (anonymous):

at least for some rather small value of \(n\) you know \(\sin(\frac{1}{n})<1\) to be more precise

OpenStudy (anonymous):

so you just use the comparison test?

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