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Mathematics 16 Online
OpenStudy (anonymous):

2x^2-3x-65=0

OpenStudy (praxer):

$$\huge x= \frac{-b\pm\sqrt{b^2-4ac}}{2a}$$ This is the formula to find the roots of the equation.

OpenStudy (anonymous):

X=13/2

OpenStudy (anonymous):

I have no idea what I'm doing

OpenStudy (praxer):

Quadratics equations are of the form ax^2+bx+c The equation which you posted is also of this form. Where a=2; b=-3;c=-65 Now, plug this value into the equation posted above and you will find the value of x for which the equation is ZERO. In other terms you will find the roots of the equation. Did you understand this.? :)

OpenStudy (anonymous):

Yes. Thank you

OpenStudy (praxer):

Welcome.:)

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