Question

2i/3-4i write as a complex number in standard form

Answer 1

Standard form = a+ib

Answer 2

\[\frac{2i}{3-4i}\times \frac{3+4i}{3+4i}\] does it
and this works because \[(a+bi)(a-bi)=a^2+b^2\] a real number

Answer 3

Rationalise the denominator as we don't want i in the denominator