Question

Find a numerical value of one trigonometry function of x. (1+tanx)/(1+cotx)=2

Answer 1

1. convert all the trigo functions into sines and cosines first

Answer 2

and then...

Answer 3

Looks like this is not working...

Answer 4

Okay let t be tan(x) then

Answer 5

I,m sorry I don't really understand how to solve it.

Answer 6

\[\begin{array}{rclr}
\frac{1+t}{1+\frac1t}&=&2&t\ne-1\\
1+t&=&2(1+\frac1t)&t\ne-1\\
1+t&=&2+\frac2t&t\ne-1\\
t+t^2&=&2t+2&t\ne-1\\
t^2-t-2&=&0&t\ne-1\\
(t-2)(t+1)&=&0&t\ne-1\\
t-2=0&or&t+1=0&t\ne-1\\
t=2&or&t=-1(rej.)&t\ne-1\\
t&=&2
\end{array}\]

Answer 7

Tell me if there's any step you don't understand

Answer 8

i got it ; )

Answer 9

Yay :D

Answer 10

did you see the attachment I just uploaded?

Answer 11

yes

Answer 12

Another Q.
Verify that each equation is an I identity.
\[\sin(A+\pi)=-sinA\]

Answer 13

Take
\[
x=\tan^{-1}(2)
\]

Answer 14

\[
\tan ^{-1}(2.)=1.10715
\]

Answer 15

Thank you ; )

Answer 16

YW