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Find the vectors.
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In the diagram, OA → = 4a, OC → = 2c and CB → = a. (a) Express BA → in terms of a and c. (b) OP → = 2a – c. Explain why OP → is parallel to BA →. (c) Find area of a triangle OBA ------------------ area of a triangle OPA
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OA = OC + CB + BA 4a = 2c + a + BA
solve BA
(ii) OP=2a-c and BA=3a-2c SO OP//BA because each are linear relation of a,-c
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(iii) (OBA)=1/2|OBxOA|=1/2|(2c+a)x(4a)|=4/2(2c x a+a x a)=4c x a=4|c|*|a|*sin(c,a)
do the same to find (OPA)
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