If (-1, y) lies on the graph of y = 22x, then y =
in this orderd pair (-1,y) what is the value of x ?
@Bonka14 can you answer me ?
I have no clue thats what I'm trying to figure out..
okay an ordered pair is always respresented as (x,y) and here you have (-1,y) what is x ?
Im not sure but my answer choices are -4, 1/4, or 1
is that all the problem If (-1, y) lies on the graph of y = 22x, then y = or is there something else ?
Yes that all it says but the problem is If (-1, y) lies on the graph of y = 2^2x, then y = is what? -4 1/4 1
If just realized on the problem it didn't put the "^" sign.
okay so I'm gonna help you with this one you have (-1,y) then x=-1 (because an ordered pair is represented as (x,y)) and you have this point (-1,y) lies on the graph of y=2^2*x so all you have to do is to put the value of x in y=2^2*x is it clear ?
So i multiply the x by the -1?
no you put instead of x its value
oh okay so it would be -1
Right..
NO wait thats not right.
so your answer is :
1? o_O lol im so confused.
okay slowly (-1,y) ----> x=-1 is it clear til here ?
Yes so far so good
Ohh okayy so Would it be -4? Would that be my answer..
okay, this point (-1,y) belongs to the graph of y=2^2*x so it satisfies it's equation is that clear ?
yes.
good to simplify things, what is a graph ; it contains all the points that satisfies it's equation for example y=2^2*x if x=0 ----> y=2^2*0=0 if x=1-----> y=2^2*1=4*1=4 if x=2-----> y=2^2*2=4*2=8 did you got it ?
Oh okay yes i did thank you!!(:
so can you give now the anwser of your question
1/4
first do you have \[y=2^2x\] or something else?
@Bonka14
no..
what is the expression then can you draw it ?
is it \[y=(2^2)^x\]
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