Question

how do you find the solution set for 2x^2 is greater than or equal to 8?

Answer 1

have you tried 2?

Answer 2

Does it looks like \[2x^\ge 8\]

Answer 3

NO

Answer 4

First replace inequality sign by equality so we get 2x^2 = 8

Answer 5

you don't need to

Answer 6

\[\frac{ 2x^2 }{ 2 } \ge \frac{ 8 }{ 2 } \ge \sqrt{x^2} \ge \sqrt{4}\]

Answer 7

solve for x by merely isolating it

Answer 8

get rid of 2 by dividing both sides by 2
then get rid of the exponent by obtaining it's equivalent root - the square root

Answer 9

I am lost

Answer 10

I know 2 is the square root of 4 but how does that give you the solution set?