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jigglypuff314 (jigglypuff314):
A particle moves on the x-axis so that its position at any time t (greater than equal to) 0 is given by x(t) = 2t(e^-t) Is the particle speeding up or slowing down at time t = 0? Could someone pwease help me with this? :3
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OpenStudy (anonymous):
find the sign if v(0) and a(0)
OpenStudy (anonymous):
speeding up if same sign slowing down if opposite signs
jigglypuff314 (jigglypuff314):
v(0) = 3 Ad a(0)= negative number :P ?
jigglypuff314 (jigglypuff314):
oh, so slowing down?
OpenStudy (anonymous):
well, if the math is correct, then yes
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jigglypuff314 (jigglypuff314):
Ok thank you! :) ... ... ... I can't find the close button on this app 0.o darn it
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