Question

A particle moves on the x-axis so that its position at any time t (greater than equal to) 0 is given by x(t) = 2t(e^-t)
Is the particle speeding up or slowing down at time t = 0?

Could someone pwease help me with this? :3

Answer 1

find the sign if v(0) and a(0)

Answer 2

speeding up if same sign
slowing down if opposite signs

Answer 3

v(0) = 3
Ad a(0)= negative number :P ?

Answer 4

oh, so slowing down?

Answer 5

well, if the math is correct, then yes

Answer 6

Ok thank you! :)

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