Question

Find tangent line equation to the curve y = y(x) at the point (-1,1) if the function y(x) is defined implicitly by the equation (x^2+y^2)^2=4*x^2*y

Answer 1

\[(x^2+y^2)^2=4x^2y \]\[2(x^2+y^2)(2x+2yy')=8xy+4x^2y'\] plug in the numbers, solve for \(y'\)