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\(CE \times ED = AE \times EB\) CE = 10 ED = 6 AE = 4 EB = x So \(10 \times 6 = 4x\) \(60 = 4x\) Solve for x
Alright X=15
Remember, If two chords intersect in a circle, the product of the lengths of the segments of one chord equal the product of the segments of the other.
Algebra and Geometry :D How I missed getting tutored by you.
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