Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

how do I solve for "x=√4x+5" (square root of 4x+5)

OpenStudy (anonymous):

square both sides x^2 = 4x+5 x^2 - 4x -5 = 0 standard quadratic equation form

OpenStudy (anonymous):

Awesome, thanks!

OpenStudy (anonymous):

Nice compliment. You are very welcome.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!