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80% of all CA drivers wear seat belts. If 3 drivers are pulled over, what's the probability that all would be wearing their seat belts?
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\[.8\times .8\times .8=.8^3\]
we need to write it as a % to the nearest 10th.
ok
and can you show me the calculation?
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use a calculator type in \(.8^3\) and see what you get
don't know how. sorry
Got it. Can we continue
a nationwide survey showed 65% of all children in the united states dislike eating veges. if 3 children are chosen at random. what is the probability that all 3 dislike eating veges. writen as a % to the nearest 10th.
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please include the calculation.
would that be .27
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