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Mathematics 8 Online
OpenStudy (anonymous):

80% of all CA drivers wear seat belts. If 3 drivers are pulled over, what's the probability that all would be wearing their seat belts?

OpenStudy (anonymous):

\[.8\times .8\times .8=.8^3\]

OpenStudy (anonymous):

we need to write it as a % to the nearest 10th.

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

http://mathforum.org/library/drmath/view/56510.html

OpenStudy (anonymous):

and can you show me the calculation?

OpenStudy (anonymous):

use a calculator type in \(.8^3\) and see what you get

OpenStudy (anonymous):

don't know how. sorry

OpenStudy (anonymous):

http://www.wolframalpha.com/input/?i=.8^3

OpenStudy (anonymous):

Got it. Can we continue

OpenStudy (anonymous):

a nationwide survey showed 65% of all children in the united states dislike eating veges. if 3 children are chosen at random. what is the probability that all 3 dislike eating veges. writen as a % to the nearest 10th.

OpenStudy (anonymous):

please include the calculation.

OpenStudy (anonymous):

would that be .27

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