Question

identify the conic (y-4)^2=16(x+1)

Answer 1

parabola is'nt it

Answer 2

It is a parabola

Answer 3

We have 2 different types of equation for a parabola
\[(x-k)^2=2p*(y-h)\]
or
\[(y-k)^2=2p*(x-h)\]
This parabola is the second type, so
\[(y-4)^2=16*(x+1)\]
Is a Parabola.