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Mathematics 21 Online
OpenStudy (anonymous):

4sinθcosθ= √3

OpenStudy (anonymous):

Is there a question?

OpenStudy (anonymous):

Basically just solve it over the interval 0<θ<2pi

OpenStudy (superdavesuper):

You can use this equation sin2A=2sinAcosA to solve the prob.

OpenStudy (anonymous):

yeah i figured. I got stuck on one of the steps

OpenStudy (anonymous):

i got as far as sin(2θ)=√3/2

OpenStudy (superdavesuper):

√3/2 is a special case: see the unit circle pic here: http://upload.wikimedia.org/wikipedia/commons/thumb/4/4c/Unit_circle_angles_color.svg/720px-Unit_circle_angles_color.svg.png

OpenStudy (anonymous):

thanks

OpenStudy (superdavesuper):

Welcome

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