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Calculus1 21 Online
OpenStudy (stamp):

Differentiate the following: \[y=log(8x^2-3x+9)\]

OpenStudy (stamp):

\[y'=\frac{ 1 }{ (8x^2-3x+9) }*16x-3\]\]

OpenStudy (mathstudent55):

What is the derivative of log u? Use that plus the chain rule.

OpenStudy (stamp):

thank you

OpenStudy (mathstudent55):

Correct. Make sure 16x - 3 is in parentheses or it's simply the numerator of the fraction.

OpenStudy (stamp):

word

OpenStudy (mathstudent55):

\(y'=\dfrac{16x-3 }{8x^2-3x+9 } \)

OpenStudy (mathstudent55):

You're welcome.

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