Question

The probability that a train leaves on time is 0.7. The probability that the train arrives on time and leaves on time is 0.56. What is the probability that the train arrives on time, given that it leaves on time?

0.7

0.8

0.49

0.56

Answer 1

divide

Answer 2

\[P(A|B)=\frac{P(A\cap B)}{P(B)}\] in your case \(P(A\cap B)=.56\) and \(P(B)=.7\)

Answer 3

0.8 @satellite73