Question

-3x^4+27x^2+1200=0
find all zeros of the equation!

Answer 1

@Hero PLEASE HELP D: ive been on this for 3 hours

Answer 2

Please show WORK. NO GRAPHING. I NEED WORK. I have some, but i cant get the correct answer.

Answer 3

First, pull out the GCF.

-3x^4+27x^2+1200=0

-3(x^4 - 9x^2 - 400) = 0

Find two factors that have a product of 400 and a sum of 9.

-3(x^4 - 25x^2 + 16x^2 - 400) = 0

-3(x^2(x^2 - 25) + 16(x^2 - 25)) = 0

-3(x^2 + 16)(x^2 - 25) = 0

-3(x^2 + 16)(x + 5)(x - 5) = 0

(x^2 + 16) ---> x^2 = -16 ---> this doesn't count because sqrt -16 cannot be done.

(x + 5) ---> x = -5
(x - 5) ---> x = 5

The zeros are x = 5 and x = -5.

Answer 4

also 4i and -4i?

Answer 5

Personally, I've never been asked for those solutions when I've done these types of problems.

Answer 6

oh ok well u did good! Can i ask u a different question?????

Answer 7

If it's something similar, yes.

Answer 8

What is the equation of y=x^3 with the given transformations? vertical stretch by a factor of 3,horizontal shift 4 units to the right, vertical shift 3 units down.

Answer 9

It doesn't seem like I know how to do that...

What grade is this? Just curious.

Answer 10

10 algebra 2

Answer 11

Well, I'm doing Algebra 1 :).

Answer 12

oh wow