Question

Determine two pairs of polar coordinates for the point (3, -3) with 0° ≤ θ < 360°.

a. (3squareroot2, 315°), (-3squareroot2 , 135°)

b. (3squareroot2, 225°), (-3squareroot2 , 45°)

c. (3squareroot2, 45°), (-3squareroot2 , 225°)

d. (3squareroot2 , 135°), (-3squareroot2 , 315°)

Answer 1

someone!

Answer 2

\[
\left\{3 \sqrt{2} \cos (315 {}^{\circ}),3 \sqrt{2} \sin (315
{}^{\circ})\right\}=\{3,-3\}\\
\left\{-3 \sqrt{2} \cos (135 {}^{\circ}),-3 \sqrt{2} \sin (135
{}^{\circ})\right\}=\{3,-3\}
\]
So the answer is a