Question

Find the area of a regular hexagon with a 48-inch perimeter.

Answer 1

For an hexagon of lateral,
\[l=P/6\] You have the formula,
\[A=3{l^2\cdot\frac{\sqrt{3}}{2}}=\frac{3\sqrt{3}}{2}(P/6)^2\] With P=48 in this case, the perimeter.