Help!!!! Part A: What is the y-intercept of the function and what does this tell you about the car? (4 points) Part B: Calculate the average rate of change of the function represented by the table between x = 1 to x = 3 and what does the average rate represent? (4 points) Part C: What would be the domain of this function if the car traveled the same rate until it reached its destination? (2 points)
The table for it
@iPwnBunnies
@ganeshie8
Please help
for the second part , Average rate of the change of the function is y2-y1/x2-x1 , where (x1,y1),(x2,y2) are the starting and ending points respectively therefore average rate change between x = 1 , to x = 3 wud be 750-850/3-1 = -100/2 = -50
Did this make any sense to u? O_O
Wouldn't the y intercept be 900
Oh yes Nvm! It wont be equation but it wud be x+1 is directly proptional to y+100 , Good call there! , when x is 0 , y is 900 so y-intercept is 900
Okay then it asks what does it tell me about the car?
I'm not sure how to explain that
well it just tells u that when time is 0 , car is 900 miles away from the destination
Theres no other thing it could possibly tell abt the car...... .-. Dint make sense eh?
No it makes sense and for C?
if car is travelling from the same rate , that means distance is going to decrease in the intervels of 50 miles until it becomes 0. 0 900 1 850 2 800 3 750 4 700 5 650 6 600 7 550 8 500 9 450 10 400 11 350 12 300 13 250 14 200 15 150 16 100 17 50 18 0 YAY! Reached the destination !, jesus christ it took so much effort to type all dat So Domain wud be all the numbers from 0 to 18 or u can write [0,18]
Lol! Sorry thank you can you help me with more questions
#2
ok well.lets call the rent y and days x then rate of change of function wud be dy/dx = 625-465/7-5 = 160/2=80 Now to write it in the standard x, y form take the dx to the otherside and integrate the equation \[\int\limits dy =80\int\limits dx \] that would make it y = 80x + c (constant)
Okay, sorry but going back up to number one for part B what does the average rate of change represents
Well it represents the average speed for the first question
average speed of the car
It represents the average speed of the car from one hour to the next?
Yeap!
Okay back to #2
now going back to the second question we got y = 80 x + c now we gotta find c u can place value of x , y from the given values that is 465 and 5 that makes our equation 465 = 80 x 5 +c 465 = 400 + c c = 65 therefore our genral equation is now y = 80 x + 65
is that clear?
Yes , as a function notation would I just add fx to the end of it?
Yes!
Actually in place of y , u have to write F(x)
Yeah, okay how would I do part c
well just alot random values to x and see what value y will get , and mark those points in graph, for instance when x = 0 , y = 65 so our point on the graph would be (0,65) take three-four such points by assigning values to x , and join those points
Okay what do they mean by intervals ?
intervals are the difference between the values of the y
and differnce in the values of x
Okay
#3
well slope of the function wud be dy/dx so slope of f(x) 7-(-9)/1-1 = infinite while the slope of g(x) = d/dx(3x-2) = 3
I got 8 for the slope
Oh my bad 7-(-9) / 1-(-1) = 16/2 that would be 8
plus g(x) 's y intercept wud be 3(0)-2 = -2 and f(x)'s y intercept is -1 so F(x) has greater y intercept
How do the slope s compare, they're both positive?
Yeap But g(x) has larger value of slope so it wud be less bent toward X-axis
You mean fx has a larger slope
Ah yes! 8 is of F(x) right? then yes xD sorry i can hardly keep my eyes open its 8 Am here xD
Oh, I'm sorry lol . #4
isnt this the same question? O_O
Sorry
this relation isnt a function as a function cannot have different images for the same x in the domain
So every x has to have their own individual output?
Yes! one value of x cannot have two different values of y , in the given relation 1 has two values of y (0,-1) , therefore its not a function
and in the second part to find f(4) just put the value of x as 4 in the equation that will give u the value of f(4)
and In part C an ordered pair is---> (x,y) so when x is p , y would be -p+6 so ordered pair will be (p , 6-p)
got it eh? O_O
One moment I'm looking at it
Okay I got it
#5
f(w) total weight will be weight of the trucks + n x weight of each bale therefore f(w) = 4500+150n f(w) = 150(30 + n)
for part b put n as 15 that will make f(w) = 150(30+15) = calculate that
for part c , a cartoon worth 20Kg(Eh? must be daffy duck,oh waits Its carton ,idk why i read that as cartoon :/) is also added to the truck so now total wait wud be f(w) = 150(30+10) + 20 f(w) = 150(300) + 20 = 45020 (idk if thats correct, calculate) :/
Okay, thank you so much!
thats all? *whew* No worriez
You're amazing
gee thanks! glad to help
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