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Physics 18 Online
OpenStudy (idkwut):

A test charge of 1.0 × 10^-5 C is at a point in an electric field where the field strength is 2.0 × 10^4 N/C. What is the magnitude of the force experienced by the test charge and in what direction is the force compared to the field?

OpenStudy (idkwut):

a. 0.20 N, opposite direction b. 0.10 N, opposite direction c. 0.10 N, same direction d. 0.20 N, same direction

OpenStudy (idkwut):

@Nali

OpenStudy (nali):

|dw:1398394534551:dw|

OpenStudy (nali):

|dw:1398394601337:dw|

OpenStudy (idkwut):

E is the strength??

OpenStudy (idkwut):

It is 0.20 N. Which direction will it be?

OpenStudy (nali):

it is the same direction since the Q is positive which means that the Electric field direction is the same as the force direction |dw:1398394955452:dw|

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