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Mathematics 7 Online
OpenStudy (anonymous):

tan(-x)/cot(-x) = ?

OpenStudy (atlas):

Remember cot x = 1/tan x

OpenStudy (anonymous):

1

OpenStudy (atlas):

no

OpenStudy (atlas):

Tan x * cot x =1 ; since they are inverse of each other

geerky42 (geerky42):

\[\dfrac{\tan(-x)}{\cot(-x)} = \dfrac{\tan(-x)}{\dfrac{1}{\tan(-x)}} = \tan^2(-x)\]

geerky42 (geerky42):

Since \(\tan(-x) \ -tan(x)\), \(\tan^2(-x) = --tan^2(x) = \boxed{\tan^2(x)}\)

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