Question

cos[sin^-1(3/5) - cos^1(3/5)]

Answer 1

hint: let

\[\Large x = \sin^{-1}\left(\frac{3}{5}\right)\]
\[\Large y = \cos^{-1}\left(\frac{3}{5}\right)\]

Answer 2

so you'll end up with cos(x-y)

break this up using the identity

cos(x-y) = cos(x)cos(y) + sin(x)sin(y)

Answer 3

please that doesn't help i'm so lost

Answer 4

ok let's draw a right triangle