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MIT 8.01 Physics I Classical Mechanics, Fall 1999 26 Online
OpenStudy (anonymous):

can you help me with this problem a particle is projected from a certain point .it is noticed that its range on the horizontal plane which passes through the point of projection is equal to three times the maximum height above the point of projection and the velocity after two seconds from the time of projection is equal to the velocity of projection . find the velocity of projection

OpenStudy (anonymous):

Velocity of projection = 5[\sqrt{13}\]

OpenStudy (anonymous):

Time of flight = 2 seconds ! and Range=3 height ! apply kinematics eqn

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