Mary has a bag that contains 5 green marbles, 7 red marbles and 9 blue marbles. Without looking, Mary draws a marble from the bag. What is the probability that Mary will draw a red or a green marble?

a.4/7

b.1/20

c.5/63

d.1/12

Question

Mary has a bag that contains 5 green marbles, 7 red marbles and 9 blue marbles. Without looking, Mary draws a marble from the bag. What is the probability that Mary will draw a red or a green marble?

a.4/7 

b.1/20

c.5/63

d.1/12

irishboy123 · Answer

Red + green = 12
Total = 21

Got it?!

anonymous · Answer

5 + 7 + 9 = 21. $$\frac{ 5 }{ 21 } \times \frac{ 7 }{ 21 }$$ reduce if needed. $$\frac{ 5 }{ 21 }\times \frac{ 1 }{ 3 }$$ Solve and you have your answer. :)

anonymous · Answer

That is if the problem is asking P(red, then green). :)

anonymous · Answer

5/63

anonymous · Answer

Correct! :D

anonymous · Answer

if g(x)=x^2+3x-7  find g(-3)

a.
11
c.
–43
b.
7
d.
–7

anonymous · Answer

@Friends1

anonymous · Answer

Hmmm....hold on. Haven't done these type of problems in quite some time. :)

anonymous · Answer

ok

zarkon · Answer

you might want to look at that probability question again