Question

help!!

Answer 1

XD beyond me lol

Answer 2

I would do this.

\(\LARGE\color{blue}{ \bf a_n=4n-3 }\) is the recursive formula.

\(\LARGE \color{blue}{ \bf a_1=4(1)-3=4-3=1 }\)
\(\LARGE\color{blue}{ \bf a_{10}=4(10)-3=40-3=37 }\)

\(\LARGE\color{blue}{ \bf S_{10}=5(a_1+ a_{10})~/~2=? }\)

Answer 3

hold on...

Answer 4

\(\LARGE\color{blue}{ \bf S_{10}=(a_1+ a_{10}) \div 2 \times 10 }\)

Answer 5

ognore the s_10 in my first blue post, and use the last one I wrote just now.

Answer 6

(a1+a10 ) / 2 is the average term

times 10, to find the sum.

Answer 7

so what would I plug in would it be 4*1+3*10?