Question

Find the value of the discriminant for the following quadratic equation:

2x2 + 6x + 5 = 0

Answer 1

Discriminant i.e. D=b^2-4ac

Answer 2

\[\Delta = b ^{2}-4ac\]

Answer 3

Where:
\[ax ^{2}+bx+c =0\]

Answer 4

here a=2
b=6
c=5
therefore
D= 6^2-4(2X5)
D= 36-40
D=-6

Answer 5

if \[\Delta > 0 = \] real roots