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Mathematics 20 Online
OpenStudy (anonymous):

please HELP 3 question, giving medal.

OpenStudy (anonymous):

Question 5 (Multiple Choice Worth 1 points) (07.01) Mike packed an equal number of flashlights in each of x gift boxes. The number of compartments in each gift box was 3 more than the number of boxes. The number of flashlights in each compartment of a box was 2 more than the number of compartments in each box. The expression below shows the total number of flashlights that Mike packed in all the boxes: x(x + 3)(x + 5) Which expression shows the number of flashlights in each compartment? x + 3 x + 5 (x + 3)(x + 5) x(x + 3)(x + 5) Question 6 (Multiple Choice Worth 2 points) (07.01) Organize the following polynomial expressions from least to greatest based on their degree: x + 2xyz 3x + y + z 2x3y + y2x - 3x + 4 9x3yz II, III, I, IV III, I, IV, II I, II, IV, III II, I, III, IV Question 7 (Multiple Choice Worth 2 points) (07.01) Organize the following expressions from greatest to least by number of terms: x + 2xyz 3x + y + z 2x2y + x2 - 3x + 4 9x2yz III, II, I, IV III, I, IV, II I, II, IV, III II, I, III, IV

OpenStudy (johnweldon1993):

Well we let box = x Compartments = 3 more than x so (x + 3) Flashlights = 2 more than number of compartments....so (x + 5)

OpenStudy (johnweldon1993):

for 2) Degree = Exponent so which ever is bigger (3 as opposed to 2 for example) will go in front

OpenStudy (johnweldon1993):

for 3) each term (you can see is seperated by a + or - sign here so x + 2 would have 2 terms...etc...so order that from most terms to least terms

OpenStudy (anonymous):

wait so number one is just x+5

OpenStudy (johnweldon1993):

Correct (it just wants what part of that long function is the flashlight part...which is the x + 5

OpenStudy (anonymous):

ok thx

OpenStudy (anonymous):

so the second question is A. @johnweldon1993

OpenStudy (anonymous):

no never mind it would be C

OpenStudy (anonymous):

i just need help with the last question.

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