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you and 4 friends go to a concert in how many different ways you can sit in the assigned seats? a.24 b.20 c.48 d.120
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c
Assuming there are only 4 seats for the 4 people then there are a total of \[4!=4 \times 3 \times 2 \times 1 = 24\] possible ways to sit. They way to think about this is: there are 4 choices for who can sit in the first seat, then 3 choices for the second seat and so on. When you get to the last seat there is only one person left and she has to sit there.
so its not c
oh k i got it wrong for the first time it 24
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