A rectangle has a perimeter of 26 feet. Twice its length (l) is one foot more than three times its width (w). What is the length of the rectangle, in feet?

A.

5

B.

13

C.

8

D.

16

Question

A rectangle has a perimeter of 26 feet. Twice its length (l) is one foot more than three times its width (w). What is the length of the rectangle, in feet?




A. 

5 


B. 

13 


C. 

8 


D. 

16

anonymous · Answer

perimeter of rectangle = 2*(Length+width)
as per problem
2L+1 = 3W where L = length and W = width
plug the value of width in the formula for perimeter
hope u can determine length now

texaschic101 · Answer

P = 2L + 2W
P = 26
2L = 3W + 1...... L = 3/2W + 1/2
now sub
26 = 2(3/2W + 1/2) + 2W
can you solve it from here ? First solve for W, then sub that back in and solve for L.