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A bag contains 3 blue marbles, 9 green marbles, and 11 yellow marbles. Twice you draw a marble and replace it. Find P(blue, then green) a) 27/529 b) 27/23 c) 15/529 d) 12/23
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D. 12/23
The answer is not D!
And stop just giving answer. Read the Code of Conduct.
renabanans, on the first draw you want a blue 3 of the 23 marbles are blue so that probability is 3/23 You then PUT IT BACK so for the second draw 9 of the 23 marbles are green that probability is 9/23 The draws are independent. So multiply your 2 probabilities for the CORRECT answer.
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