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Cot^2x/cscx+1=cscx-1
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\[\frac{ \cot^2(x) }{ \csc(x)+1 } = \csc(x) -1 \] If this correct?
Do you want to prove it, or find the x's which make it true?
Yes
Prove it
cot(x) = cos(x)/sin(x) therefore: cot^2(x) = (cosx/sinx)(cosx/sinx) csc(x) = (1/sinx)
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