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A pile of logs has 24 logs in the bottom layer, 23 in the second layer, 22 in the third, and so on. The top layer contains 10 logs. Find the total number of logs in the pile.
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This is an arithmetic series. You need to find the sum of: 24 + 23 + 22 +..... + 10 First find the number of terms in the series. Sum of the arithmetic series = (first term + last term) / 2 * number of terms in the series.
S = 24 + 22/2* 14 ?
I mean 24 +10/2*14
There are 15 terms in the series (you can count them from 24 to 10). S = (24 + 10) /2 * 15
Thank a lot !
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