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how to factor this question 9p-p^3 is this the answer p(3+p)^2
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You are taking out a p from \(9p-p^3\), which results in \(p(9-p^2)\). Now, you have a difference of two squares, which factors to: \(9(3+p)(3-p)\). You just have to memorize the difference of two squares factored form. \((a^2-b^2)\) factors to \((a+b)(a-b)\).
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