Question

The perimeter of a rectangle is 62. The area of the same rectangle is 234. Which of the following equations could be used to find the dimensions of the rectangle? : w(31-w)=234, w(62-2)=234, w(31+w)=234, or w(62+w)=234

Answer 1

A:w(31-w)=234
B:w(62-2)=234
C:w(31+w)=234
D:w(62+w)=234

Answer 2

Perimeter / 2 = 31, or one length plus one width.

Answer 3

we have the perimeter equation: 2l+2w = 62 and solve it for l and put that value in the area equation: lw = 234 in place of l and see what we get...

Answer 4

l = 31-w ?

Answer 5

yeah A...

Answer 6

Okay, I see it now. Thanks!

Answer 7

pleasure