Question

Find the vertex form of the following equation by completing the square.
y=3x^2+6x+8
A. y=(x+4)^2
B. y=3(x+2)^2+4
C. y=3(x+1)^2+5
D. y=(x+3)^2+5
Please Help

Answer 1

Put it in vertex form!

f(x) = a(x -h)^2 + k

Answer 2

Take the "x" term and divide it by 2 and square it.

3(x^2+2x + 1) +8
-3

3(x^2 + 2x + 1) + 5

f(x) = 3(x+2)^2 + 5

Answer 3

Sorry typo,

f(x) = 3(x + 1)^2 + 5

Answer 4

ok yeah I just got that thanks!!