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Solve for x √3x-5=2 A.no solution B.7/3 C.–1 D.3 Please Help
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root is over 3x only or over 5 too
over both
First square both sides & simplify it for x
take square on both sides...
making it \[3x-5=4\]
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it will be (√3x-5)^2 = (2)^2 ... it will cancel the root... and you will obtain an equation like... 3x-5=4... now solve ofr x...
then \[3x-5+5=4+5\]
yeah
\[3x \div3=9\div3\]
yeah :-)
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\[x=3\]
yeah...
Thanks so much!
good :-)
pleasure
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