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Please help establish the identity. 1-[(sin^2v)/(1+cosv)]= cosv
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\[1- \frac{\sin^2v}{1+cosv}=\cos{v}\] \[\frac{1+cosv}{1+cosv}- \frac{\sin^2v}{1+cosv}=\cos{v}\] \[\frac{1+cosv-\sin^2v}{1+cosv}=\cos{v}\] \[\frac{(1-\sin^2v)+cosv}{1+cosv}=\cos{v}\] \[\frac{\cos^2v+cosv}{1+cosv}=\cos{v}\] \[\frac{cosv(cosv+1)}{(1+cosv)}=\cos{v}\]got it from here ?
amazing!
Tnx, my best class 98 in trig :))))
What about the previous one, do you need help with it ?
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