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Mathematics 13 Online
OpenStudy (anonymous):

Since the Kentucky Derby is coming up what is the probability of somebody betting on and getting the first, second and third place horses in the correct order?

OpenStudy (anonymous):

How many total horses are involved?

OpenStudy (anonymous):

as today 24

OpenStudy (anonymous):

So for this problem you'll use the nCr application on your calculator.

OpenStudy (kropot72):

There are 24P3 permutations of the 24 runners taken 3 at a time. Only one of these permutations has first second and third in the correct order. Therefore the required probability is: \[P(first\ 3\ having\ correct\ order)=\frac{1}{24P3}=\frac{1}{24\times23\times22}=you\ can\ calculate\]

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