Any help is appreciated! Solve the equation for x. Identify any extraneous solutions. √x=-3 I know the answer is (+9) but is (-9) an extraneous solution? I'm not sure what an extraneous solution is. Thanks!
an extraneous solution is basically a value that seems to work when solving an equation, when in reality it doesn't work
for this problem, you can't have a negative value under a square root sign, so -9 should not be a solution
So it is NOT an extraneous solution? @11calcBC
if my memory is accurate, yes
Thanks!
somebody confirm this...
Can you confirm this @tkhunny ?
\(\sqrt{x} = -3\) You do NOT know the answer is x = +9. That is incorrect. The answer is also not x = -9. This equation has no solution in the Real Numbers. The Domain if \(f(x) = \sqrt{x}\) is \(x \ge 0\). This eliminates \(x = -9\) The Range if \(f(x) = \sqrt{x}\) is \(f(x) \ge 0\). This eliminates \(x = 9\)
\(\sqrt{9} = 3 \ne -3\)
Thanks again @11calcBC !!!
no problem :D
What was your final answer?
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