Question

Using trig to find area in polygons, can anyone help?

Answer 1

Ok, so I think I solved it but I'm not sure, so if someone could confirm that i'm right, that would be great :) Here's the shape:

I'm think I need to make the 30-60-90 triangle, then use:
\[\sin 30 = \frac{ s }{ 5 }\]
(s is for side by the way)

Answer 2

That's what that would look like.