Question

evaluating limits

Answer 1

simply plugin \(x = \dfrac{\pi}{2}\)

Answer 2

and evaluate

Answer 3

\[\lim \limits_{x\to \frac{\pi}{2}} (2e^x\sin(x)) = 2e^{\frac{\pi}{2}}\sin(\frac{\pi}{2}) = ?\]

Answer 4

why pi/2? cant it be something easy like 1? cuz the problem you just wrote is even more complicated than what it started with .-.

Answer 5

@ganeshie8

Answer 6

:/

Answer 7

\[\lim \limits_{x\to \frac{\pi}{2}} (2e^x\sin(x)) = 2e^{\frac{\pi}{2}}\sin(\frac{\pi}{2}) = 2e^{\frac{\pi}{2}} *1 = 2e^{\frac{\pi}{2}}\]

Answer 8

we're done.