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Algebra
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2c+6 over4-c * 4c-16 over 5c +15
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\[\frac{ 2c+6 }{ 4c }\times \frac{ 4c-16 }{ 5c+16 }\]
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Factor those expressions!
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i dont know how!!!
Okay, no problem. 2c+ 6 can be factored. Both terms are actually being multiplied by the same number (2). So we can factor out a 2 and get the following (2)(c+3) I didn't change anything about the expression besides what it looks like.
Can you factor anything out out 4c-16 and 5c+15
one sec
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