Question

│y + 4│< 1
a. -5 < y < -3
b. -3 < y < 5
c. -4 < y < 1
d. 1 < y < 4

Answer 1

\(\large │y + 4│< 1\implies
\begin{cases}
+(y + 4)< 1
\\ \quad \\
-(y + 4)< 1
\end{cases}\)
solve both scenarios for "y"

recall that when multiplying by a negative value, in an inequality you have to flip the sign