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Find the area of the regular polygon. Give the answer to the nearest tenth. decagon with a side of 4 cm A. 123.1 cm2 B. 129.4 cm2 C. 246.2 cm2 D. 139.8 cm2
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Area of regular polygon of side length \(s\) : \(\large \dfrac{ns^2}{4} \cot (\frac{\pi}{n})\)
simply plugin \(s\), \(n\) values and evaluate
n = number of sides s = length of side
ohhh thanks for clarifying batman
Np, so give this a shot, and get back to us :P
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Actually since we're using a decagon you can easily just use this: \[A = \frac{ 5 }{ 2 }a^2\sqrt{5+2\sqrt{5}}\] Where a is the side.
40^2/4 =400
decagon has 10 sides
It's A !
Correcto!
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